Let's say I'm a baker with 10 rolls. As I understand, every roll counts as a vote so I have 10 votes towards any proposal. If someone wants to delegate his 5 rolls to me in cycle N, when will his 5 rolls be counted towards to my votes? Would my votes count be the same as my baking roll count(10 rolls) at cycle N? Would that mean I have to wait until ~cycle N + 7 to have 15 votes?
The stake of each delegate is computed at the beginning of each voting
period.
If a voting period starts at cycle n, your rolls are counted at the very end of cycle n-1 and that value is used for the whole period, that is up to cycle n+8.
Roll count towards voting is independent of roll count towards staking.
Look at this baker, for example: they had a large delegation (2 million + XTZ) that caused them to be overdelegated, and the delegator moved to another baker before cycle N + 7 came. But their vote was accounted for with 243 rolls, which will only be in effect for staking purposes in upcoming cycle 84
Thanks for answering. Is there other evidence that 243 rolls are accounted for in this scenario? I looked into the actual operation, the rolls accounted is not part the operation. This means that tzscan is doing some calculation to get this and they *could* be wrong. I mostly would love to see some other proof (preferably on chain or rpc that the number of votes were counted).
私が10ロールのパン屋だとしましょう.私が理解しているように、すべてのロールは投票としてカウントされるので、私はどんな提案に対しても10票を持っています.誰かがサイクルNで彼の5つのロールを私に委任したい場合、彼の5つのロールはいつ私の投票にカウントされますか?投票数は、サイクルNでのベーキングロール数(10ロール)と同じですか?それは、15票を獲得するために〜サイクルN + 7まで待たなければならないことを意味しますか?